2x^2+5x=(2x^2+17x+35)

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Solution for 2x^2+5x=(2x^2+17x+35) equation: 



2x^2+5x=(2x^2+17x+35)

We move all terms to the left:

2x^2+5x-((2x^2+17x+35))=0



We calculate terms in parentheses: -((2x^2+17x+35)), so:

(2x^2+17x+35)

We get rid of parentheses

2x^2+17x+35

Back to the equation:

-(2x^2+17x+35)



We get rid of parentheses

2x^2-2x^2+5x-17x-35=0

We add all the numbers together, and all the variables

-12x-35=0

We move all terms containing x to the left, all other terms to the right

-12x=35

x=35/-12

x=-2+11/12

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